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 The complete question that I got was to prove that (x'y'z)'zxywz equals xyz boolean booleanlogic booleanexpression booleanoperations demorganslaw Share Improve this question edited Oct 23 '14 at 1730 kjhughesVXhdfg`^k efVXVk dZf\Vc^ `c^Y^ ^ dWad\`V cbdYih Wqhr Xdgefd^XZcq la^`db ^a^ mVgh^mcd X aäWdb X^Z W e^grbccdYd fVfnc^å VXhdfV Dave Roberson Ministries The Family Prayer Center PO Box 725 Tulsa, OK wwwdaverobersonorgSee the answer See the answer See the answer done loading

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 The answer is x, z, y, w because density of each object is w = g/cm cubed x = 24 g/cm cubed y = 01 g/cm cubed z = 18 g/cm cubedBasic Math Examples Rewrite the equation as xxyz = w x x y z = w Subtract x x from both sides of the equation Divide each term by xz x z and simplify Tap for more steps Divide each term in x y z = w − x x y z = w x by x z x z Simplify x y z x z x y z x zQuestion If x(z) = Z(zn)z3, then X(w) w = π/2 (a) j (b)3r/2 c) (π/2)3 (d) None above This problem has been solved!

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